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A nylon tennis string on a racket is under a tension of 250 N. If its diameter is1.00 mm, by how much is it le
A nylon tennis string on a racket is under a tension of 250 N. If its diameter is1.00 mm, by how much is it lengthened from its un-tensioned length of 30.0 cm?
♠ here we apply Hook’s law: ΔL = (1/G)*F*L/S, where L=30cm =0.30m, F=250N, S=pi*r^2 is area of cross-section, r= 1/2 mm =0.0005m is radius of the string, G is coefficient of extension for nylon, ΔL is by-how-much-L-is-lengthened by F;
♣ if G=1.4·10^9 N/m^2 then
ΔL = (1/G)*F*L/S =
= (1/1.4·10^9) *250*0.30 /(pi*0.0005^2)= 6.8 cm;


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